SOLUTION: Assume that a researcher randomly selects 14 newborn babies and counts the number of girls selected, X. The probabilities corresponding to the 14 possible values of X are summarize
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Question 1200095: Assume that a researcher randomly selects 14 newborn babies and counts the number of girls selected, X. The probabilities corresponding to the 14 possible values of X are summarized in the given table. Answer the question using the following table.
X(girls) 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14
P(X) 0.000 0.001 0.006 0.022 0.061 0.122 0.183 0.209 0.183 0.122 0.061 0.022 0.006 0.001 0.000
Find the probability of selecting 11 or more girls.
Answer by math_tutor2020(3817) (Show Source): You can put this solution on YOUR website!
Given table:
| X(girls) | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 |
| P(X) | 0.000 | 0.001 | 0.006 | 0.022 | 0.061 | 0.122 | 0.183 | 0.209 | 0.183 | 0.122 | 0.061 | 0.022 | 0.006 | 0.001 | 0.000 |
Sometimes it's better to transpose the table.
This means each row becomes a column, and vice versa.
We go from a wide table to a tall table.
| X(girls) | P(X) |
| 0 | 0.000 |
| 1 | 0.001 |
| 2 | 0.006 |
| 3 | 0.022 |
| 4 | 0.061 |
| 5 | 0.122 |
| 6 | 0.183 |
| 7 | 0.209 |
| 8 | 0.183 |
| 9 | 0.122 |
| 10 | 0.061 |
| 11 | 0.022 |
| 12 | 0.006 |
| 13 | 0.001 |
| 14 | 0.000 |
It's up to you which you prefer better.
Use the last four items of the table to say the following:
P(11 or more girls) = P(11 girls) + P(12 girls) + P(13 girls) + P(14 girls)
P(11 or more girls) = 0.022+0.006+0.001+0.000
P(11 or more girls) = 0.029
Extra side notes:- Luckily we only have four things to add, so it's not too tedious to do this by hand. Spreadsheet software is recommended for larger projects.
- The instructions mention "14 possible values of X", but in reality there are 15 values. Going from X = 1 to X = 14 consists of 14 values. Then X = 0 is the 15th value.
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