SOLUTION: Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby This method is designed to increase the likelihood that

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Question 1199947: Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby This method is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect, so the probability of a girl is 0.5. Assume that the groups consist of 44 couples.
(a) through (c) below.
a) Find the mean and the standard deviation for the numbers of girls in groups of 44 births.
The value of the mean is U=.
The value of the standard deviation is o=
b) Use the range rule of thumb to find the values separating results that are significantly low or significantly high.
Values of significantly low.
girls are ?
Values of significantly high.
girls are?
c) Is the result of 43 girls a result that is significantly high?
What does it suggest about the effective ness of the method?
The result significantly high, because 43 girls is
girls. A result of 43 girls would suggest that the method

Answer by textot(100)   (Show Source): You can put this solution on YOUR website!
**a) Find the mean and the standard deviation for the numbers of girls in groups of 44 births.**
* **Mean (μ):**
* μ = n * p
* Where:
* n = number of births (44)
* p = probability of a girl (0.5)
* μ = 44 * 0.5 = 22
* **Standard Deviation (σ):**
* σ = √(n * p * (1 - p))
* σ = √(44 * 0.5 * 0.5)
* σ = √11
* σ ≈ 3.32
**Therefore:**
* The value of the mean is **μ = 22**.
* The value of the standard deviation is **σ ≈ 3.32**.
**b) Use the range rule of thumb to find the values separating results that are significantly low or significantly high.**
* **Range Rule of Thumb:**
* Significantly low values: μ - 2σ
* Significantly high values: μ + 2σ
* **Calculate:**
* Significantly low: 22 - 2 * 3.32 ≈ 15.36
* Significantly high: 22 + 2 * 3.32 ≈ 28.64
**Therefore:**
* Values of significantly low girls are **approximately 15 or fewer**.
* Values of significantly high girls are **approximately 29 or more**.
**c) Is the result of 43 girls a result that is significantly high? What does it suggest about the effectiveness of the method?**
* **Yes, the result of 43 girls is significantly high.** This is because 43 girls exceed the significantly high threshold of approximately 29 girls.
* **A result of 43 girls would suggest that the method might be effective in increasing the likelihood of having girls.** However, it's crucial to remember that this could also be due to random chance. Further investigation and larger sample sizes would be needed to draw more definitive conclusions about the effectiveness of the method.
**In summary:**
* The mean number of girls in groups of 44 births is 22, and the standard deviation is approximately 3.32.
* Using the range rule of thumb, significantly low and high values are around 15 or fewer girls and 29 or more girls, respectively.
* A result of 43 girls is significantly high, suggesting that the method might be effective, but further research is necessary to confirm this.

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