SOLUTION: The company has difficulties in supplying raw materials. The probability that the company will not be fully supplied with raw materials in each individual month is equal to 0.2. Wh

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Question 1198729: The company has difficulties in supplying raw materials. The probability that the company will not be fully supplied with raw materials in each individual month is equal to 0.2. What is the probability that the company will be fully supplied with raw materials for no more than 10 months during the year?
Answer by ikleyn(52866)   (Show Source): You can put this solution on YOUR website!
.
The company has difficulties in supplying raw materials.
The probability that the company will not be fully supplied with raw materials in each individual month
is equal to 0.2. What is the probability that the company will be fully supplied with raw materials
for no more than 10 months during the year?
~~~~~~~~~~~~~~~~~

This problem is a binomial distribution with the parameters

    n = 12    (the number of trials, equal to the number of months in a year);

    k <=10   (the number of success trials);

    p = 0.8 = 1 - 0.2  (the probability of individual success);  1-p = 0.2.


The probability is  

    P = P(0) + P(1) + P(2) + . . .  + P(10). 

    In the standard short form,  P = P(n=12, k<=10, p=0.8) =  = .


     To facilitate my calculations, I used online calculator at this site  https://stattrek.com/online-calculator/binomial.aspx

     It provides nice instructions  and  a convenient input and output for all relevant options/cases.


          The resulting number is P = 0.7251  (rounded).    ANSWER

Solved.

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If you want to see many similar  (or different)  solved problems,  look into the lessons
    - Simple and simplest probability problems on Binomial distribution
    - Typical binomial distribution probability problems
    - How to calculate Binomial probabilities with Technology (using MS Excel)
    - Solving problems on Binomial distribution with Technology (using MS Excel)
    - Solving problems on Binomial distribution with Technology (using online solver)
in this site.

After reading these lessons,  you will be able to solve such problems on your own,
which is your  PRIMARY  MAJOR  GOAL  visiting this forum  (I believe).



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