Hi Normal Distribution: µ = 15 and σ = 6 Using TI or similarly an inexpensive calculator like an Casio fx-115 ES plus a. P(x>8) = 1 - P(x ≤ 8) = 1 - normcdf(-9999, 8,6, 15) = 1 - .1217= .8783 b. Continuous Curve: P(x ≤ 8) = P(x < 8) = .1217*** c. Would it be unusual to find a service call to last at most 8 minutes Yes, it is rare*** Wish You the Best in your Studies.