SOLUTION: The diameters of oranges found in the orchard of an orange farm follow a normal distribution with a mean of 120mm and a standard deviation of 10mm. The smallest 15% of oranges (tho

Question 1197724: The diameters of oranges found in the orchard of an orange farm follow a normal distribution with a mean of 120mm and a standard deviation of 10mm. The smallest 15% of oranges (those with the smallest diameters) cannot be sold and are therefore given away. What is the cut-off diameter in this case if oranges with the smallest 15% of diameters are to be given away?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!


Hi  
 Normal Distribution: µ = 120mm and σ = 10mm  
Smallest 15% to be given away.
What is the cut-off diameter

Using TI or similarly an inexpensive calculator like an Casio fx-115 ES plus
Invnorm(.15) =  -1.0364
  10*(-1.0364) + 120 = 109.636mm 
Nearest whole number, cut-off diameter = 110mm
Wish You the Best in your Studies.

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