Hi P(due to bad weather) = .02 P(Late IS actually due to bad weather) =.82 P(wrongly diagnosed) = .03 0r 1- .03 = .97 = P(rightly diagnosed) P(that a late arrival is attributed to bad weather was actually due to bad weather) P( due to bad weather | rightly diagnosed) P(A|B) = P(A and B)/P(B) = (.02)(.82)/.97 Wish You the Best in your Studies.