Hi The probability that a bomber hits its target on any particular run is 80%. n = 3, p(hitting target) = .8, P(not hitting target) = .2 P(no hits) = (.2)(.2)(.2) = .008 P(at lest one hit) = 1 - P(x=0) = 1 - .008 = .992 Wish You the Best in your Studies.