Hi Binomial Probability: n = 30, p = 3/30 = .1 what then is the probability that the inspector's sample contains: Using TI or similarly an inexpensive calculator like an Casio fx-115 ES plus P( x = 0) = .0424 0rP(0) = 1(.1^0)(.9^30) = .0424 P(x ≥ 1) = 1 - P(x = 0) = 1 -.0424 = .9576 Wish You the Best in your Studies.