Hi n = 36 µ = 22.25 and σ = 1.50 a)SE = 1.50 / √36 = 1.5/6 = .25 b) Within what interval would you expect the sample mean to fall, with 99 percent probability? Interval is 22.25 ± ME 99% confience interval: z = 2.576 ME = 2.576(.25) = 1.394 22.25 -1.394< < 22.25 + 1.394 CI(20.856, 23.644) Wish You the Best in your Studies.