SOLUTION: According to flightstats.com, American Airlines flights from Dallas to Chicago are on time 78.2% of the time. Suppose 15 of these flights are randomly selected and the number of

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Question 1197156: According to flightstats.com, American Airlines flights from Dallas to Chicago are on time 78.2% of the time.
Suppose 15 of these flights are randomly selected and the number of on-time flights is recorded.

Calculate the probability that 9 or fewer of the selected flights were on time. Enter your answer as a decimal rounded to four decimal places.
Answer by ikleyn(52798)   (Show Source): You can put this solution on YOUR website!
.

It is a standard binomial distribution problem.

Number of trials is 15; number of success trials <= 9; the probability of each success trial is p=0.782.


The standard formula is

    P = P(n=15; k <= 9; p= 0.782) =  = .


     To facilitate my calculations, I used online calculator at this site  https://stattrek.com/online-calculator/binomial.aspx

     It provides nice instructions  and  a convenient input and output for all relevant options/cases.


          The resulting number is P = 0.08719  (rounded).    ANSWER

Solved.

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If you want to see many similar  (or different)  solved problems,  look into the lessons
    - Simple and simplest probability problems on Binomial distribution
    - Typical binomial distribution probability problems
    - How to calculate Binomial probabilities with Technology (using MS Excel)
    - Solving problems on Binomial distribution with Technology (using MS Excel)
    - Solving problems on Binomial distribution with Technology (using online solver)
in this site.

After reading these lessons,  you will be able to solve such problems on your own,
which is your  PRIMARY  MAJOR  GOAL  visiting this forum  (I believe).



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