Hi Ten percent of the tools produced in a certain manufacturing process turn out to be defective: p = .10 , n = 10 a) P(exactly two 0f the ten will be defective) = binompdf(n, p, x-value) binompdf(10, .10, 2) = .1937 a) P(exactly two of the ten will be defective) = poissonpdf(mean, x-value). n = 10, p = .10 mean= np = .10 (10) = 1 poissonpdf(1,2) = .1839 Wish You the Best in your Studies.