You are given three facts :


    - The probability that an international flight leaving the United States is delayed in departing (event D) is 0.35.


    - The probability that an international flight leaving the United States is a transpacific flight (event P) is 0.40.


    - The probability that an international flight leaving the U.S. is a transpacific flight and is delayed in departing is .14.

          This event is the intersection of events D and P, so you are given the probability of intersection of these events

               p( D ∩ P ) = 0.14.


The problem's question asks about the conditional probability  P(D|P).


By the definition, for any two events P and D, the conditional probability  P(D|P) is this fraction

               p(D|P) = p ( D ∩ P ) / p(P).


Substitute the given data into this formula, and you will get


              p(D|P) =  = 0.35.


It is your ANSWER :   The probability that an international flight leaving the United States is delayed in departing 
                      given that the flight is a transpacific flight is 0.35.

To answer this question, you should sheck if  p ( D ∩ P ) = p(D) * p(P).


Left  side is 0.14 (given).

Right side is 0.35*0.4 = 0.14.


Hence the events D and P are independent.