SOLUTION: Counting numbers are to be formed using only the digits 5, 4, 6, 2, 8, 1, 7, and 3. Determine the number of different possibilities for two digits numbers.

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Question 1196358: Counting numbers are to be formed using only the digits 5, 4, 6, 2, 8, 1, 7, and 3. Determine the number of different possibilities for two digits numbers.
Found 2 solutions by greenestamps, ikleyn:
Answer by greenestamps(13203)   (Show Source): You can put this solution on YOUR website!


The problem is not defined well enough; there are (at least) two possible interpretations.

(A) If the digits must be different: 8 choices for the first digit, then 7 for the second -- number of possible 2-digit numbers: 8*7 = 56

(B) If the two digits can be the same: 8 choices for each digit -- number of possible 2-digit numbers: 8*8 = 64

By the way, for your information.... The term is "2-digit number", not "two digits number".
Answer by ikleyn(52858)   (Show Source): You can put this solution on YOUR website!
.

Hey,  how your problem is worded,  it perplexes me . . .

The correct wording is this: 

    How many 2-digit numbers can be written using the digits 5, 4, 6, 2, 8, 1, 7 if

      (a) repeating is allowed ?

      (b) repeating is not allowed ?


To write correctly,  read from good sources.

Or consider to hire somebody, who will edit your writing.



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