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A bag contains 8 red marbles, 3 blue marbles and 5 green marbles.
If three marbles are drawn out of the bag, what is the exact probability
that all three marbles drawn will be green?
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At the start, there are 8 + 3 + 5 = 16 marbles in the bag.
Of them, 5 marbles are green.
The probability that the first drawn marble is green equals .
After that, we have 15 marbles in the bag with 4 green marbles.
So, the probability that the first two drawn marbles are green equals .
Analyzing further in the same way, we find that the probability
that the first three drawn marbles are green equals
= reduce the fractions = = = . ANSWER
Solved.
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Ignore the solution by @MathLover1, since it is totally wrong.
It is a good/classic example on how this problem SHOULD NOT be solved.
Avoid such errors in the future ( ! )
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After reading the post by Alan, I find it necessary to explain
on how to read the problem and what does it really mean.
When such problem goes without explicit pointing on " with or without replacement ",
then by DEFAULT and by the context, it ALWAYS means " without replacement ".