SOLUTION: For a confidence level of 85% for a mean with n = 16, find the critical value t. Enter the answer to 2 decimal places.

Question 1195558: For a confidence level of 85% for a mean with n = 16, find the critical value t.
Enter the answer to 2 decimal places.
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
confidence level is 85% = .85
number of sample elements is 16.
you want to find the critical t-value. rounded to 2 decimal places.
you could be looking for a 2 sided confidence level or a one sided confidence level.
the number of degrees of freedom is equal to the sample size minus 1 = 15.
your alpha or significance level is 1 - .85 = .15
you can use a calculator or you can use a table.
the calculator i used is found at https://calculator-online.net/critical-value-calculator/
i selected critical value for t.
i entered significance level of .15 with 15 degrees of freedom.
i clicked on calculate and the calculator told me (scroll down if it's not shown) that:
one-tailed critical t-value = 1.0735 = 1.07
two-tailed critical t-value = 1.5172 = 1.52
the confidence level is usually two tailed, so go with 1.52 unless otherwise instructed.

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