.
How many 5-digit numbers can be formed using numbers 0, 1, 2, …9, such that repetition is NOT allowed
~~~~~~~~~~~~~~~~~
Any of 9 digits at the most-left position, giving 9 possible options;
(any of ten digits, except of 0);
Any of remaining 10-1 = 9 digits at the next position, giving 9 possible options;
Any of remaining 9-1 = 8 digits at the next position, giving 8 possible options;
Any of remaining 8-1 = 7 digits at the next position, giving 7 possible options;
Any of remaining 7-1 = 6 digits at the next position, giving 6 possible options.
Thus in total, there are 9*9*8*7*6 = 27216 different 5-digit numbers as described.
Solved, answered and explained.
---------------
The lesson to learn from my solution is that a leading digit can not be 0 (zero).