Event E: 2 blacks are transferred at first. P(E)=(8C2)/(12C2) = 14/33 Event F: 1 black and 1 white are transferred at first. P(F)=[(4)(8)]/(12C2) = 16/33 Event G: 2 whites are transferred at first. P(G)=(4C2)/(12C2) = 1/11 Result of E: 4W,10B in basket B Result of F: 5W,9B in basket B Result of G: 6W,8B in basket B P(E then White) = (14/33)(4/14) = 4/33 P(F then White) = (16/33)(5/14) = 40/231 P(G then White) = (1/11)(6/14) = 1/77 P[(E then White) OR (F then White) OR (G then White)] = 4/33+40/231+1/77 = 71/231 --------------------------------------- P(F|White) = P(F and White)/P(White) =(40/231)/(71/231) = 40/71 Edwin