SOLUTION: Please help me solve this Basic Counting Principle problem:
Consider the following.
(a) In how many different ways can a player select a club and a diamond from a deck of 52 br
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Question 1194951: Please help me solve this Basic Counting Principle problem:
Consider the following.
(a) In how many different ways can a player select a club and a diamond from a deck of 52 bridge cards?
ways
(b) In how many different ways can a player select one card of each suit from a bridge deck?
ways
Found 2 solutions by Alan3354, greenestamps:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
(a) In how many different ways can a player select a club and a diamond from a deck of 52 bridge cards?
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A club is 1 of 4 = 1/4
Then the diamond is 13/51
The product is 13/204
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(b) In how many different ways can a player select one card of each suit from a bridge deck?
The 1st is 1/4
Then 13/51
Then 13/50
Then 13/49
Multiply those.
Answer by greenestamps(13203) (Show Source): You can put this solution on YOUR website!
Neither problem is clearly defined. I will assume....
(1) without replacement
(2) order does not matter
(a) a club and a diamond
On the first draw, there are 52 cards to choose from, of which 26 are okay (13 clubs and 13 diamonds). P = 26/52 = 1/2.
On the second draw, there are 51 cards remaining, of which 13 are okay (the 13 of the suit that was not drawn on the first draw). P = 13/51.
ANSWER: (1/2)(13/51) = 13/102
(b) one card of each suit
1st draw: 52 cards; can choose any. P = 52/52 = 1
2nd draw: 51 cards remaining; can choose any of the 39 in the 3 remaining suits. P = 39/51 = 13/17
3rd draw: 50 cards remaining; can choose any of the 26 cards in the 2 remaining suits. P = 26/50 = 13/25
4th draw: 49 cards remaining; must choose one of the 13 cards in the last remaining suit. P = 13/49
ANSWER: (1)(13/17)(13/25)(13/49)
Use a calculator and express the result in the desired/required form.
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