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Three light bulbs are selected in succession from 15 bulbs of which 5 are defective.
If the each bulb drawn is returned every after drawing, find the probability
that exactly one defective bulb is selected.
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This problem is on the binomial probability distribution.
The number of trials is 3; the number of succesful trials is 1 (one);
the probability of the success is p = = (getting a defective bulb).
Therefore, the probability under the problem's question is
P = = = . ANSWER
Solved.