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In how many ways can 9 gifts be divided between 4 children
if the eldest child is to receive 3 gifts and each of the other children 2 gifts?
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There are = = 84 choices for the eldest child;
then = 15 choices for the next (second) child;
= 6 choices for the next (third) child;
and finally only one choice without any possible options for the last child.
In all, there are = 84*15*6 = 7560 different ways to distribute the gifts under given conditions.
Solved.
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This problem is on Combinations and on Fundamental counting principle.
On these subjects, see the lessons
- Introduction to Combinations
- PROOF of the formula on the number of Combinations
- Problems on Combinations
- Fundamental counting principle problems
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Combinatorics: Combinations and permutations".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.