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(a) 5! = 5*4*3*2*1 = 120 arrangements (permutations).
(b) 5*4 = 20 2-letter words, if 2 letters are used at a time.
(c) 5*4*3*2 = 120 4-letter words, if 4 letters are used at a time.
Solved.
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Since the order is important, this problem is on PERMUTATIONS.
On Permutations, see introductory lessons
- Introduction to Permutations
- PROOF of the formula on the number of Permutations
- Simple and simplest problems on permutations
- Special type permutations problems
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Combinatorics: Combinations and permutations".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.