SOLUTION: Suppose a fair coin is tossed three times. Let X be the random variable that represents the number of heads obtained. Find the cumulative distribution function of X.

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Question 1193590: Suppose a fair coin is tossed three times. Let X be the random variable that represents the number of heads obtained. Find the cumulative distribution function of X.
Found 2 solutions by yurtman, ikleyn:
Answer by yurtman(42)   (Show Source): You can put this solution on YOUR website!
**1. Determine the Probability Mass Function (PMF) of X**
* **Possible Values of X:**
* X = 0 (no heads): TTT
* X = 1 (one head): HTT, THT, TTH
* X = 2 (two heads): HHT, HTH, THH
* X = 3 (three heads): HHH
* **Probabilities:**
* P(X = 0) = 1/8
* P(X = 1) = 3/8
* P(X = 2) = 3/8
* P(X = 3) = 1/8
**2. Define the Cumulative Distribution Function (CDF)**
* The CDF, denoted as F(x), gives the probability that the random variable X is less than or equal to a specific value (x).
**3. Calculate the CDF for Each Possible Value of X**
* **F(x) = P(X ≤ x)**
* F(x) = 0 for x < 0
* F(x) = P(X = 0) = 1/8 for 0 ≤ x < 1
* F(x) = P(X = 0) + P(X = 1) = 1/8 + 3/8 = 1/2 for 1 ≤ x < 2
* F(x) = P(X = 0) + P(X = 1) + P(X = 2) = 1/8 + 3/8 + 3/8 = 7/8 for 2 ≤ x < 3
* F(x) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 1/8 + 3/8 + 3/8 + 1/8 = 1 for x ≥ 3
**Therefore, the cumulative distribution function (CDF) of X is:**
* F(x) = 0 for x < 0
* F(x) = 1/8 for 0 ≤ x < 1
* F(x) = 1/2 for 1 ≤ x < 2
* F(x) = 7/8 for 2 ≤ x < 3
* F(x) = 1 for x ≥ 3

Answer by ikleyn(52797)   (Show Source): You can put this solution on YOUR website!
.

The answer in the post by the other tutor is incorrect and is written in absurdist form.

In this problem, the random variable X has the values 0, 1, 2, 3.

The right form for the cumulative distribution function in this problem is

    F(x) = 1/8  for x = 0;

    F(x) = 1/2  for x = 1;

    F(x) = 7/8  for x = 2;

    F(x) =  1   for x = 3.



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