SOLUTION: Find the mean ,variance , and standard deviation of the probability distribution of the random variable X, which can take only the values 1, 2 and 3 given P(1)=10/33 , P(2)=1/3, a

SOLUTION: Find the mean ,variance , and standard deviation of the probability distribution of the random variable X, which can take only the values 1, 2 and 3 given P(1)=10/33 , P(2)=1/3, a

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Question 1192579: Find the mean ,variance , and standard deviation of the probability distribution of the random variable X, which can take only the values 1, 2 and 3 given P(1)=10/33 , P(2)=1/3, and P(3)=12/33. Show the solutions.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
mean is 1*10/33 +2*11/33+3*12/33
=68/33 or 2.06
variance is (-1.06)^2(10/33)+(-0.06)^2(11/33)+ 0.94^2 (12/33)
=0.34+0.12+0.32
=0.78
sd is sqrt(0.78)=0.88
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