SOLUTION: A box contains 6 white balls and 4 red balls. We randomly (with replacement) draw two balls from the box. C) What is the probability that the second ball selected is red, given t

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Question 1191435: A box contains 6 white balls and 4 red balls. We randomly (with replacement) draw two balls from the box.
C) What is the probability that the second ball selected is red, given that the first ball selected is white?
D) What is the probability that the first ball selected is white, given that the second ball selected is red?

Answer by ikleyn(52803) About Me  (Show Source):
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A box contains 6 white balls and 4 red balls. We randomly (with replacement) draw two balls from the box.
C) What is the probability that the second ball selected is red, given that the first ball selected is white?
D) What is the probability that the first ball selected is white, given that the second ball selected is red?
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(C)  Since each drawing is with replacement, it does not matter for the second ball, what was selected at the first draw.

     The starting configuration before the second drawing is the same as before the first draw: 6 white balls and 4 red balls.

     The probability that the second ball selected is red is  P = 4%2F%286%2B4%29%29 = 4%2F10 = 0.4 = 40%.    ANSWER



(D)  Since each drawing is with replacement, it does not matter for the first ball, what was selected at the second draw.

     The starting configuration before the first drawing is  6 white balls and 4 red balls.

     The probability that the first ball selected is white is  P = 6%2F%286%2B4%29%29 = 6%2F10 = 0.6 = 60%.    ANSWER

Solved, answered and explained.