It is a typical binomial distribution problem. The probability of the success (arrive safely) in each single trial is 1/9 = 0.111111. The number of trials is n= 6; the number of successful trials is k= 3. The formula for the probability is P(n= 6; k= 3; p= 0.111111) == = 0.019268316, or 0.01927 (rounded). ANSWER