SOLUTION: Over a period of three months during one year, an airline's rate of involuntarily denying boarding was 0.85 per 10,000 passengers. What is the probability that in the

Question 1190726: Over a period of three months during one year, an airline's rate of involuntarily denying boarding was 0.85 per 10,000 passengers.
What is the probability that in the next 10,000 passengers, there will be no one involuntarily denied boarding?

Answer by ikleyn(52873) (Show Source): You can put this solution on YOUR website!
.
.
Over a period of three months during one year, an airline's rate of involuntarily
denying boarding was 0.85 per 10,000 passengers.
What is the probability that in the next 10,000 passengers,
there will be no one involuntarily denied boarding?
~~~~~~~~~~~~~~~~~

Assume that the rate remains the same in the next 10,000 passengers.

The probability that a passenger will involuntary denyed boarding is  P =  = 0.000085.


The probability that a passenger will not involuntary denyed boarding is the complement

      P' = 1 - 0.000085 = 0.999915.


The probability that in the next 10,000 passengers, there will be no one involuntarily denied boarding is

       = 0.427399491,  or   0.4274 = 42.74%  (rounded).      ANSWER

Solved.

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SOLUTION: Over a period of three months during one​ year, an​ airline's rate of involuntarily denying boarding was 0.85 per​ 10,000 passengers. What is the probability that in the

SOLUTION: Over a period of three months during one year, an airline's rate of involuntarily denying boarding was 0.85 per 10,000 passengers. What is the probability that in the