SOLUTION: Events A & B are independent. Suppose Event A occurs with a probability 0.60 and Event B occurs with a probability of 0.74. A) Compute the probability that B occurs but A does

Question 1190604: Events A & B are independent. Suppose Event A occurs with a probability 0.60 and Event B occurs with a probability of 0.74.
A) Compute the probability that B occurs but A does not occur.
B) Compute the probability that either A occurs without B or A and B both occur.
Answer by ikleyn(52797) (Show Source): You can put this solution on YOUR website!
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Events A & B are independent. Suppose Event A occurs with a probability 0.60 and
Event B occurs with a probability of 0.74.
A) Compute the probability that B occurs but A does not occur.
B) Compute the probability that either A occurs without B or A and B both occur.
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Since events A and B are independent, the probability

    P(A & B) = P(A)*(P(B) = 0.60*0.74 = 0.444.


(A)  the probability that B occurs but A does not occur = P(B) - P(A & B) = 0.74 - 0.444 = 0.296.    ANSWER


(B)  the probability that either A occurs without B or (A & B) both occur = 

         =                  (P(A) - P(A & B))       +   P(A & B)          = P(A) = 0.60.    ANSWER

Solved.

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