SOLUTION: A small dealership leased 21 Suburu Outbacks on 2-year leases. Two years later, when the cars were returned, the mileage was recorded (see below). Is the dealer’s mean significa
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Question 1188602: A small dealership leased 21 Suburu Outbacks on 2-year leases. Two years later, when the cars were returned, the mileage was recorded (see below). Is the dealer’s mean significantly different from the national average of 30,000 miles for 2-year leased vehicles, using the 10 percent level of significance? (a) What is the appropriate testing method? Please write down each step of hypothesis testing for this case. (b) Please solve this problem and show the process and the output file. (20 points total)
40060, 24960, 14310, 17370, 44740, 44550, 20250,
33380, 24270, 41740, 58630, 35830, 25750, 28910,
25090, 43380, 23940, 43510, 53680, 31810, 36780
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
the population mean is assumed to be 30,000 (national average).
the population standard deviation is not known, therefore the sample standard deviation is used instead and the t-score is used instead of the z-score.
here's a reference on choosing between z-score and t-score.
https://math.stackexchange.com/questions/1817980/how-to-know-when-to-use-t-value-or-z-value
the statistics for the sample given was determined by use of the online descriptive statistics calculator at https://www.calculatorsoup.com/calculators/statistics/descriptivestatistics.php
from this calculator, it was determined that:
the sample mean was 33949.5238.
the sample standard deviation was 11866.174.
the sample size was 21.
10% level of significance equals 90% confidence interval.
two tail 90% confidence interval has 5% tail on each end.
critical t-score with 20 degrees of freedom (sample size minus 1) = plus or minus 1.742718218.
this was determined through the use of the ti-84 plus scientific calculator, but could also have been determined through the online calculator found at https://www.omnicalculator.com/statistics/critical-value
at critical t-score of plus or minus 1.742718218, use the t-score formula to find the raw score.
that formula is t = (x - m) / s
t is the t-score.
x is the sample mean.
m is the assumed population mean.
s is the standard error.
the standard error is the standard deviation of the distribution of sample means.
the formula for that is:
s = standard deviation / square root of sample size.
that becomes:
s = 11866.174 / sqrt(21) = 2589.411455.
the test t-score was determined to be:
t = (33949.5238 - 30000) / 2589.41455 = 1.525257437.
since this was less than the critical t-score of 1.742718218, the results of the test were not significant, indicating there was not enough evidence to say that the mean scores for the dealership were different than the mean scores of the population.
here's a display of the descriptive statistics for the sample.
here's a display of the results of using the online critical t-value calculator.
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