SOLUTION: A fitness center is interested in finding a 95% confidence interval for the mean number of days per week that Americans who are members of a fitness club go to their fitness center

Question 1187071: A fitness center is interested in finding a 95% confidence interval for the mean number of days per week that Americans who are members of a fitness club go to their fitness center. Records of 219 members were looked at and their mean number of visits per week was 2.4 and the standard deviation was 1.8. Round answers to 3 decimal places where possible.

b. With 95% confidence the population mean number of visits per week is
between ____ and _____ visits.
c. If many groups of 219 randomly selected members are studied, then a different confidence interval would be produced from each group. About ____
percent of these confidence intervals will contain the true population mean number of visits per week and about _____ percent will not contain the true population mean number of visits per week.

Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
half-interval is a t(0.975, df=218)*s/sqrt(n)
=1.971*1.8/sqrt(219)
=0.234
interval is (2.160, 2.634) units visits
95% and 5% are the other answers.
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