SOLUTION: The time spent waiting in the line is approximately normally distributed. The mean waiting time is 6 minutes and the variance of the waiting time is 4. Find the probability that a
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Question 1186328: The time spent waiting in the line is approximately normally distributed. The mean waiting time is 6 minutes and the variance of the waiting time is 4. Find the probability that a person will wait for between 7 and 8 minutes. Round your answer to four decimal places.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
variance is 4 min^2 so sd=2 min
z=(x-mean)/sd
z=1/2 and 1
that probability z is between those values is 0.1499.
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