SOLUTION: 66% of all Americans are home owners. If 50 Americans are randomly selected, find the probability that a. Exactly 32 of them are are home owners. b. At most 31 of them are

Algebra.Com
Question 1185800: 66% of all Americans are home owners. If 50 Americans are randomly selected, find the probability that
a. Exactly 32 of them are are home owners.
b. At most 31 of them are are home owners.
c. At least 32 of them are home owners.
d. Between 29 and 33 (including 29 and 33) of them are home owners.


Answer by ikleyn(52824)   (Show Source): You can put this solution on YOUR website!
.

It is the binomial distribution probability problem.

Use this free of charge online calculator
https://stattrek.com/online-calculator/binomial.aspx


////////////////


//   I am not a promoter of this online calculator:  my only wish is to teach you to do this simple job on your own,
       because the level of complexity of this assignment is as   1 + 2 = 3.



RELATED QUESTIONS

62% of all Americans are home owners. If 35 Americans are randomly selected, find the... (answered by Solver92311)
62% of all Americans are home owners. If 35 Americans are randomly selected, find the... (answered by textot)
69% of all Americans are home owners. If 37 Americans are randomly selected, find the... (answered by CPhill,ikleyn)
If 18% of all Americans are underweight, find the probability two randomly selected... (answered by ikleyn)
8% of all Americans live in poverty. If 30 Americans are randomly selected, find the... (answered by ewatrrr)
8% of all Americans live in poverty. If 37 Americans are randomly selected, find the... (answered by Solver92311)
16% of all Americans live in poverty. If 47 Americans are randomly selected, find the... (answered by Boreal)
8% of all Americans live in poverty. If 37 Americans are randomly selected, find the... (answered by CPhill)
The percentage of Americans who are vegetarians is 3.2%. Four people are randomly... (answered by stanbon)