SOLUTION: A distribution of values is normal with a mean of 63.6 and a standard deviation of 14.4.
Find the probability that a randomly selected value is greater than 44.9.
P(X > 44.9) =
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Question 1185731: A distribution of values is normal with a mean of 63.6 and a standard deviation of 14.4.
Find the probability that a randomly selected value is greater than 44.9.
P(X > 44.9) =
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
the mean is 63.6
the standard deviation is 14.4
my ti-84 plus calculator will tell you that the probability that a randomly selected value is greater than 44.9 is .9029612237.
this online calculator will tell you that the probability is .90296.
they both say the same thing with the only difference being in the number of decimal digits being rounded to.
here's what the results from the online calculator show you.
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