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A basket contains two apples, three lemons, and one orange. If two fruits are drawn at random with
replacement, find the probability of drawing:
a) two apples
b) one lemon on the first draw and one orange on the second draw
c) one apple and one orange
d) one lemon on the first draw only
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The notice common for parts (a), (b) and (c) is that the total number of fruits is 2 + 3 + 1 = 6.
(a) P = = = . ANSWER
The first factor is the probability to draw one of the two apples from the total of 6 fruits.
The second factor is the probability to draw the remaining single apple from the remaining 5 fruits.
(b) P = = . ANSWER
The first factor is the probability to draw one lemon from the total 6 fruits.
The second factor is the probability to draw one orange from the remaining 5 fruits.
(c) When we consider case (c), we should treat two cases P(apple,orange) + P(orange,apple).
It may be boring. There is another way using combinations
P = = = . ANSWER
(d) In case (d), I do not understand clearly what the question is, so I will not answer it.
Solved.