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Please help. A calculus professor plans classes so carefully that the length of his classes is uniformly distributed
between 100.0 min. and 105.0 min. Let x be the random variable representing the length of his randomly selected class.
Find the probability the class is greater than 103 min.
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Yesterday I solved a TWIN problem at this link
https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1183789.html
https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1183789.html
So, this time I will be short.
P = = = 0.4 = 40%. ANSWER
As always in such problems, you divide the "favorable" time interval length by the base interval length.
It is how the uniform distribution probability works.
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Comment from student : Thank you for your help! I checked the link and I noticed that problem was "less than"
while this one is "greater than). So for either way, they are solved the same?
My response : You are right. The major idea is the same
P = .
The only thing is to take care to calculate the numerator and denominator correctly.