SOLUTION: Three yam tubers are chosen at random from 15 tubers of which 5 are spoilt. Find the probability that,of the three chosen tubers: A. None is spoilt B. All are spoilt C. Exactly

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Question 1183431: Three yam tubers are chosen at random from 15 tubers of which 5 are spoilt. Find the probability that,of the three chosen tubers:
A. None is spoilt
B. All are spoilt
C. Exactly one is spoilt
D. At least one is spoilt.
Found 3 solutions by greenestamps, ikleyn, robertb:
Answer by greenestamps(13330)   (Show Source): You can put this solution on YOUR website!


deleted -- my response was not for the question that was asked
Answer by ikleyn(53751)   (Show Source): You can put this solution on YOUR website!
.
Three yam tubers are chosen at random from 15 tubers of which 5 are spoilt. Find the probability that, of the three chosen tubers:
A. None is spoilt
B. All are spoilt
C. Exactly one is spoilt
D. At least one is spoilt.
~~~~~~~~~~~~~~~~ 

(A)  In part (A), you chose, actually, 3 tubers from 10 tubers that are not spoilt, among the total of 15 tubers.


     Therefore, you can use any of two formulas to find the probability


         P =  =  =  = 0.2637  (rounded),

     or

         P =  =  =  = 0.2637  (same as above).




(B)  In part (B), you select, actually, 3 tubers from 5 spoilt tubers, among the total 15 tubers.


     Therefore, you can use any of two formulas to find the probability


         P =  =  =  = 0.0219  (rounded),

     or

         P =  =  =  = 0.0219  (the same value).



(C)  "Exactly one is spoilt" means one is spoilt of the 3 selected among the total 15, and 2 are not.


     Therefore, you can use this formula to find the probability


         P =  =  =  = 0.4945.    (rounded)



(D)  It is the complement probability to the value found in (A)


         P = 1 - 0.2637 = 0.7363   (rounded).


Solved.     //     All question are answered.



Answer by robertb(5830)   (Show Source): You can put this solution on YOUR website!
A.

B.

C.

D.
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