SOLUTION: "A study of the nicotine contents of a certain brand of cigarette shows that on the average, one cigarette contains 1.52 milligrams of nicotine with a standard deviation of 0.07 mi

Question 1183149: "A study of the nicotine contents of a certain brand of cigarette shows that on the average, one cigarette contains 1.52 milligrams of nicotine with a standard deviation of 0.07 milligrams". Between what values must the nicotine content be for: (Hint: Use Chebyshev’s Theorem)

a. At least 24/25 of all cigarettes of this brand?

b. At least 48/49 of all cigarettes of this brand?

Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
Let represent the random variable for the nicotine content of a cigarette.

Then Chebyshev's theorem states that

.

a. Let ==> ===> .
===>
==> <==> .

b. Apply the same procedure as in part (a), but now letting , which gives .
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