SOLUTION: You measure 34 watermelons weights, and find they have a mean weight of 59 ounces.
Assume the population standard deviation is 3.3 ounces.
Based on this, what is the maximal marg
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Question 1182877: You measure 34 watermelons weights, and find they have a mean weight of 59 ounces.
Assume the population standard deviation is 3.3 ounces.
Based on this, what is the maximal margin of error associated with a 99% confidence interval for the true population mean watermelon weight.
Answer as decimal, to 2 places
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
the margin of error is z*sigma/sqrt(n)
=2.576*3.3/sqrt(34)
=1.46 oz.
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