SOLUTION: Assume that a sample is used to estimate a population proportion p.
Find the 99% confidence interval for a sample of size 351 with 65% successes.
Answer as a tri-linear inequalit
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Question 1182808: Assume that a sample is used to estimate a population proportion p.
Find the 99% confidence interval for a sample of size 351 with 65% successes.
Answer as a tri-linear inequality using decimals (not percents) accurate to 3 decimal places.
_______ < p < _________
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
1-sample proportion 99%CI z-int
half interval is z(0.995)+/- sqrt (p(1-p)/n)
=2.576*sqrt (0.65*0.35/351)
=0.0656 or 0.066
add to and subtract from mean
0.584 < p < 0.716. The result may change slightly on how much z is rounded in the intermediate calculations. I took it to four decimal places.
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