SOLUTION: Assume that a sample is used to estimate a population proportion p. Find the 95% confidence interval for a sample of size 82 with 54 successes. Answer as a tri-linear inequality

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Question 1182807: Assume that a sample is used to estimate a population proportion p.
Find the 95% confidence interval for a sample of size 82 with 54 successes.
Answer as a tri-linear inequality using decimals (not percents) accurate to 3 decimal places.
_______ < p < _________

Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
p hat=54/82=0.6585
half-interval is z(0.975)*sqrt(p*(1-p)/n)
=1.96*sqrt(0.6585*0.3415/82)
=0.1026 or 0.103
The interval is (0.556, 0.761)
or 0.556 < p < 0.761

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