SOLUTION: A random sample of 225 adults was given an IQ test. It was found that 135 of them scored higher than 100. Based on this, compute a 99% confidence interval for the proportion of all

Question 1182282: A random sample of 225 adults was given an IQ test. It was found that 135 of them scored higher than 100. Based on this, compute a 99% confidence interval for the proportion of all adults whose IQ score is greater than 100. Then find the lower limit and upper limit of the 99% confidence interval.
Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. (If necessary, consult a list of formulas.)
Lower limit:

Upper limit:

Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
point estimate p hat is (135/225)=0.6
half-interval is z(0.99)*sqrt(.6*.4/225)
=2.576*0.0327
=0.0841 or 0.08
(0.52, 0.68)
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