SOLUTION: If n=26, -x(x-bar)=43, and s=17, construct a confidence interval at a 98% confidence level. Assume the data came from a normally distributed population.
Give your answers to one
Algebra.Com
Question 1181558: If n=26, -x(x-bar)=43, and s=17, construct a confidence interval at a 98% confidence level. Assume the data came from a normally distributed population.
Give your answers to one decimal place.
____ < μ < _______
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
98% half-interval is t(0.99,df=25)*sigma/sqrt(n)
=2.328*17/sqrt(26)=2.787*17/sqrt(26)=9.29 or 9.3
the interval is (33.7, 52.3)
RELATED QUESTIONS
If n=17,¯x(x-bar)=35, and s=17, construct a confidence interval at a 98% confidence... (answered by Boreal)
If n=17, ¯x (x-bar)=50, and s=13, construct a confidence interval at a 80% confidence... (answered by Boreal)
If n=29, ¯x(x-bar)=45, and s=17, construct a confidence interval at a 99% confidence... (answered by Boreal)
If n=17,¯x(x-bar)=34, and s=4, construct a confidence interval at a 99% confidence... (answered by math_tutor2020)
If n=21, ¯x(x-bar)=40, and s=20, construct a confidence interval at a 99% confidence... (answered by oscargut)
If n=21, ¯x(x-bar)=40, and s=20, construct a confidence interval at a 99% confidence... (answered by oscargut)
If n=23, -x(x-bar)=32, and s=15, construct a confidence interval at a 95% confidence... (answered by Boreal)
If n=31,
¯
x
(x-bar)=41, and s=18, construct a confidence interval at a 90%... (answered by Theo)
1. You measure 29 textbooks' weights, and find they have a mean weight of 34 ounces.... (answered by Boreal)