SOLUTION: 5) The number of calls received by a call center follows a Poisson distribution with an average of 5 calls per minute. For a 1 minute period, a. Find the expected value. b. Find

Question 1180933: 5) The number of calls received by a call center follows a Poisson distribution with an average of 5 calls
per minute. For a 1 minute period,
a. Find the expected value.
b. Find the probability of receiving no more than 2 calls.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
The mean/expected value of the Poisson distribution is the parameter, here 5 calls per minute.
no more than two calls is p(0,1,2)
probability of 0 calls is e^-5*5^0/0!=0.0067
1 call is e^-5*5^1/1!=0.0337
2 calls is e^-5*5^2/2!=0.0842
that sum is 0.1246 rounding each step 0.1247 using no rounding until the end (preferred).

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