SOLUTION: 2. The weight distribution of a sample of adults with physical inabilities is approximately normal, with mean 72 and standard deviation 8. Find an interval of values around the mea
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Question 1180572: 2. The weight distribution of a sample of adults with physical inabilities is approximately normal, with mean 72 and standard deviation 8. Find an interval of values around the mean such that it
i. Includes 95 percent of the observed values
ii. Includes almost all observed values (and thus coincides with the range, min-max).
iii. Includes 50 percent of the observed values.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
The first interval would be z=+/-1.96*sigma, to 1.96*8=15.68
This is +/- 15.68 or (56.32, 87.68) some weight units, prob kg.
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The second one would be +/-3 sd or +/- 24 , so the interval would be (48, 96)
-
The third would be +/- 0.674*8 (the 25th percentile is z=-0.674 and the 75th is z=+0.674)
+/-5.39
(66.61, 77.39)
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