.
12 opportunities for the 1-st position
11 opportunities for the 2-nd position
10 3-rd
9 4-th
8 5-th position
So, in all, there are 12*11*10*9*8 = 95040 different passwords.
Solved, answered, carefully explained, and even the standard mantra is attached - - - for your future use.
E N J O Y (!)
------------------
See the lesson
- Special type permutations problems
in this site. Find there many solved similar problems.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lesson is the part of this online textbook under the topic "Combinatorics: Combinations and permutations".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.