Hi Normal Distribution: µ = 63.6 and σ = 2.5 100 women are randomly selected: Using TI or similarly an inexpensive calculator like an Casio fx-115 ES plus Continuous curve P(x > 63.0) = P(x ≥ 63.0) = normalcdf(63, 9999, 63.6, 2.5/√100) = .9918 D.) the correct answer. Wish You the Best in your Studies.