mean of population =variance of population = [(2-6)²+(3-6)²+(6-6)²+(8-6)²+(11-6)²]/5 = 10.8 standard deviation of population = √(var) = √(10.8) = 3.286335345 [2,2] mean = 2 var = 0 [2,3] mean = 2.5 var = 0.25 [2,6] mean = 4 var = 4 [2,8] mean = 5 var = 9 [2,11] mean = 6.5 var = 20.25 [3,3] mean = 3 var = 0 [3,6] mean = 4.5 var = 2.25 [3,8] mean = 5.5 var = 6.25 [3,11] mean = 7 var = 16 [6,6] mean = 6 var = 0 [6,8] mean = 7 var = 1 [6,11] mean = 8.5 var = 6.25 [8,8] mean = 8 var = 0 [8,11] mean = 9.5 var = 2.25 [11,11] mean = 11 var = 0 ------------------------------ sums 90 67.5 mean of sample means = 90/15 = 6 variance of sample means = 67.5/5 = 13.5 standard deviation of sample means = √13.5 = 3.674234614 (a) the mean of the population, μ=6 (b) the standard deviation of the population, σ=3.286335345 (c) the mean of the sampling distribution of means, μx̄=6 (d) the standard deviation of the sampling distribution of means, i.e., the standard error of means. σx̄=3.674234614 Edwin