SOLUTION: I need help for the following questions. Really appreciate it. A sample of 40 observations is selected from one population with a population standard deviation of 3.9. The sampl

Question 1178794: I need help for the following questions. Really appreciate it.
A sample of 40 observations is selected from one population with a population standard deviation of 3.9. The sample mean is 102. A sample of 53 observations is selected from a second population with a population standard deviation of 3.2. The sample mean is 101. Conduct the following test of hypothesis using the 0.05 significance level. a. Is this a one-tailed or a two-tailed test? b. State the decision rule. c. Compute the value of the test statistic. d. What is your decision regarding Ho ? e. What is the p-value?
H0:μ1=μ2;H1:μ1≠μ2

Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!


Hi
|sample | 40 | 53 |
|Mean | 102| 101 |
|Standard Deviation | 3.9 | 3.2 |
Are the sample means no different or different?
Ho: u1 = u2
Ha: ui ≠ u2
.05 confidence level, 2 tailed t-test:  |t (df 93-2=91)| > 1.99 Reject Ho
t=(x bar-mean)/sqrt ((s1^2/n1)+(s2^2/n2))
t= (1)/sqrt ((15.21/40)+(10.24/53)) = 1.32
 1.32 <1.99 Fail to Reject Ho, study indicates statistically the sample means
are no different.
p-value = .095
Wish You the Best in your Studies.

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