SOLUTION: Samuel has two 4-sides dice. the sides of each die have the numbers 1,2,3,4. because the dice are pyramid-shaped, when Samual rolls the dice, each lands with three faces showing

Question 1178561: Samuel has two 4-sides dice. the sides of each die have the numbers 1,2,3,4. because the dice are pyramid-shaped,
when Samual rolls the dice, each lands with three faces showing and one face not showing.
if Samual rolls his dice, the probability that the number not showing have a difference of 2 is:
a. 1/9
b. 1/8
c. 1/4
d. 1/3

Found 3 solutions by MathLover1, ikleyn, greenestamps:
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

Since order doesn't matter, we have chance of select either , and , -- both make a difference of .

answer: b.
Answer by ikleyn(52803)   (Show Source): You can put this solution on YOUR website!
.
Samuel has two 4-sides dice. the sides of each die have the numbers 1,2,3,4. because the dice are pyramid-shaped,
when Samual rolls the dice, each lands with three faces showing and one face not showing.
if Samual rolls his dice, the probability that the number not showing have a difference of 2 is:
a. 1/9
b. 1/8
c. 1/4
d. 1/3
~~~~~~~~~~~~~~~

Hello,   this passage in your post

" . . . the number not showing have a difference of 2 . . ."

is   NONSENSE.

It implies that the post in whole is   NONSENSE,   too.

Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!

"...the probability that the numbers not showing have a difference of 2 is"

(1) Tutor @ikleyn chose to say that your post is nonsense because of the missing plural. I'm a bit more forgiving than that; I know what you meant to say.

(2) The other tutor gave the wrong answer.

The number of possible outcomes for the numbers not showing on the two dice is 4*4=16.

Of those, 4 combinations (not 2) have a difference of 2: 1 and 3, 3 and 1; 2 and 4, 4 and 2.

ANSWER: P(difference of 2 between the two numbers not showing) = 4/16 = 1/4.

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