SOLUTION: The mean daily production of a herd of cows is assumed to be normally distributed with a mean of 38 liters, and standard deviation of 11.3 liters. A) What is the probability tha

Question 1178429: The mean daily production of a herd of cows is assumed to be normally distributed with a mean of 38 liters, and standard deviation of 11.3 liters.
A) What is the probability that daily production is between 20.6 and 23 liters? Do not round until you get your your final answer.
Answer= (Round your answer to 4 decimal places.)
Warning: Do not use the Z Normal Tables...they may not be accurate enough since WAMAP may look for more accuracy than comes from the table.

Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
using the ti-84 plus calculator, i get the following.

mean = 38 liters.
standard deviation - 11.3 liters.
probability that daily production is between 20.6 and 23 liters is equal to .0303809369.
rounded to 4 decimal places, that makes it equal to .0304.
visually, this looks like this:

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