Hi standard normal Distribution: μ = 0 σ = 1 P(z > z0 = .05 invNorm(.05) = 1.645 = z0 small area to right (b) P(Z < z0) = 0.88 invNorm(.88) = 1.175= z0 large area to the left (c) P(Z < z0) = 0.10 invNorm(.10) = -1.282= z0 small area to the left (d) P(Z > z0) = 0.95. invNorm(.95) = -1.645= z0 large area to right Wish You the Best in your Studies.